| Chemical adjustments are vital to proper sanitation and water balance. Since adjustments are based on the volume of water in the pool or spa, it is important to calculate the volume correctly. The following formulas may be used: 1. Rectangular or square shaped pool (length x width x average depth x 7.5) |
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| Example 1 (U.S. Customary Units):length = 40 feet width = 20 feet avg. depth = 4.5 feet volume = (length x width x average depth x 7.5) 40 x 20 x 4.5 x 7.5 = 27,000 gallonsExample 2 (Metric Units):length = 12m width = 6m avg. depth = 1.5m volume = (length x width x average depth x 1,000) 12 x 6 x 1.5 x 1,000 = 108,000 liters |
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| 2. Any circular shaped pool (diameter 1 x diameter 2 x average depth x 5.9) |
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| Example 3 (U.S. Customary Units):diameter 1 = 20 feet diameter 2 = 20 feet avg. depth = 4 feet volume = (length x width x avg. depth x 5.9) 20 x 20 x 4 x 5.9 = 9,440 gallons Example 4 (Metric Units): diameter 1 = 6m |
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| 3. Circular Spa (diameter 1 x diameter 2 x average depth x 5.9)Example 5 (U.S. Customary Units):diameter 1 = 4 feet diameter 2 = 4 feet avg. depth = 3 feet volume = (length x width x average depth x 283) 4 x 4 x 3 x 5.9 = 283 gallons Example 6 (Metric Units): diameter 1 = 1.5m |
